developer puis reduire les expressions A = (a+7)(a+5) B = (x-4)(x+5) C = (+x+3)(9-x) D = (-x-1)(5-x)
Mathématiques
zidane1777
Question
developer puis reduire les expressions
A = (a+7)(a+5)
B = (x-4)(x+5)
C = (+x+3)(9-x)
D = (-x-1)(5-x)
2 Réponse
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1. Réponse loulakar
Bonjour,
A= a^2+5a+7a+35 =a^2+12a+35
B=x^2+5x-4x-20 = x^2+x-20
C=9x+27-x^2-3x = -x^2+6x+27
D = (-x-1)(5-x)
D=-5x + x^2-5+x = x^2-4x-5 -
2. Réponse Sulky
Bonjour,
A = (a + 7)(a + 5)
A= a² + 5a + 7a + 35
A = a² + 12a + 35
B = (x - 4)(x + 5)
B = x² + 5x - 4x - 20
B = x² + x - 20
C = (x + 3)(9 - x)
C = 9x + 27 - x² - 3x
C = - x² + 6x + 27
D = ( - x - 1)(5 - x)
D = - 5x + x² - 5 + x
D = x² - 4x - 5