a) 3x + 7 = x + 2 b) 2 + 2y = -1 +3y c) 4 - 5a = 2a -1 d) t - 4 = -3t - 10
Mathématiques
Algerienne61
Question
a) 3x + 7 = x + 2
b) 2 + 2y = -1 +3y
c) 4 - 5a = 2a -1
d) t - 4 = -3t - 10
b) 2 + 2y = -1 +3y
c) 4 - 5a = 2a -1
d) t - 4 = -3t - 10
2 Réponse
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1. Réponse SilversLight
[tex]A) \\ 3x + 7 = x + 2 \\ 2x + 5 = 0 \\ x = - \frac{5}{2}\\ \\ B) \\2 + 2y = -1 + 3y \\ 3 - y = 0 \\ y = 3\\\\ C) \\4 - 5a = 2a - 1 \\ 5 - 7a = 0 \\ - 7a = -5 \\ a = \frac{5}{7}\\ \\ D)\\ t - 4 = -3t - 10 \\ 4t + 6 = 0 \\ t = \frac{-6}{4} \\ t = \frac{-3}{2} \\[/tex] -
2. Réponse Anonyme
3x + 7 = x + 2
3x - x = 2 - 7
2x = - 5
x = - 5/2
2 + 2y = - 1 + 3y
2y - 3y = - 1 - 2
- y = - 3
y = 3
4 - 5a = 2a - 1
4 + 1 = 2a + 5a
5 = 7a
5/7 = a
t - 4 = - 3t - 10
t + 3t = - 10 + 4
4t = - 6
t = - 6/4
t = - 3/2