On considère l'expression :a=(x+2)(5x-1)+(5x-1)(4+3x) 1. Développer 2. Factoriser

Salut !

[tex]A = (x+2)(5x-1)+(5x-1)(4+3x) \\ \\ \\ 1) A=(x+2)(5x-1)+(5x-1)(4+3x) \\ \\ A = 5 x^{2} -x+10x-2+20x+15 x^{2} -4-3x \\ \\ A =20 x^{2} +26x-6 \\ \\ \\ 2)A=(x+2)(5x-1)+(5x-1)(4+3x) \\ \\ A = (5x-1)[(x+2)+(4+3x)] \\ \\ A = (5x-1)(x+2+4+3x) \\ \\ A = (5x-1)(4x+6)[/tex]

J'espère t'avoir aidé(e) ! :)

bonjour

a = 5 x² - x + 10 x - 2 + 20 x + 15 x² - 4 - 3 x
a = 20 x² + 26 x - 6

a = ( 5 x -1) ( x + 2 +  4 + 3x)
a = ( 5 x -1) ( 4 x + 6)