Mathématiques

Question

développer puis réduire
2 (x + 3 ) +5
7x + 9 (x - 2)
13+ 5 (3 - x)
6 ( x + 1 )+ 8 ( 3 + x )

2 Réponse

  • = 2 ( x + 3 ) + 5
    = 2 * x + 2 * 3 + 5
    = 2x + 6 + 5
    = 2x + 11

    = 7x + 9 ( x - 2 )
    = 7x + 9 * x + 9 * ( - 2 )
    = 7x + 9x - 18
    = 16x - 18

    = 13 + 5 ( 3 - x )
    = 13 + 5 * 3 + 5 * ( - x )
    = 13 + 15 - 5x
    = - 5x + 28

    = 6 ( x + 1  ) + 8 ( 3 + x )
    = 6 * x + 6 * 1 + 8 * 3 + 8 * x
    = 6x + 6 + 24 + 8x
    = 14x + 30
  •  2(x+3)+5 = 2x+6+5  = 2x+11

     7x + 9 (x - 2) = 7x + 9x-18  = 16x -18

    13+5(3-x)= 13+15-5x = 28-5x

    6(x+1) +8(3+x) = 6x+6+24+8x =14x+30



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