Mathématiques

Question

:انشر و بسط
2a(2a-5)-7(a-3)(a+1)
(2a+5).(10-a)+(12a-2).(3a-1)
y(0,5-6)+(2,5y+8)(4y-5)

2 Réponse

  • 2a(2a-5)-7(a-3)(a+1)
    4a²-10a-7(a²+a-3a-3)
    4a²-10a-7a²-7a+21a+21
    -3a²+4a+21
  • A= 2a²-10a-(7a-21)(a+1)
    A= 2a²-10a-(7a²+7a-21a-21)
    A=2a²-10a-7a²-7a+21a+21
    A=-5a²-11a+21

    B=20a-2a²+50-5a+36a²-12a-6a-2
    B=34a²-3a+48

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